[Hóa 9]

S

soccan

$SO_3+H_2O \longrightarrow H_2SO_4\\
n_{SO_3}=0,5\ mol\\
n_{H_2SO_4}=0,5+80.1,5.0,6.\dfrac{1}{98}=\dfrac{121}{98}\ mol$
$C$%$=\dfrac{121}{98}.98.\dfrac{1}{0,5.80+80.1,5}.100=75,625$%
 
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