hóa 9

N

nguyenminhduc2525

nCuO=0.02(mol)
nH2SO4=20/98=0.2 (mol)
CuO + H2SO4 >>CuSO4 + H20
0.02___0.02_____0.02
mdd=100+1.6=101.6(g)
C% CuSO4=3.2X100%/101.6=3.15%
C% H2SO4 dư = 0.18X98X100% / 101.6=18%
 
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