[Hóa 8]

Y

yumi_26

$SO_3 + H_2O -> H_2SO_4$
(mol) x..............................x

\Rightarrow $ \sum m_{H2SO_4} = 98x + 10 (g)$

$m_{dd} = 80x + 100 (g)$

Theo đề ta có:

$\dfrac{98x+10}{80x + 100}.100 = 20$ \Rightarrow x = ..
 
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