[Hoá 8] Hoá học nâng cao lớp 8

P

phankyanhls2000

a)$n_{CuO}=20:80=0,25(mol)$
$n_{CuO} pu=n_O=(20-16,8):16=0,2(mol)$
H%=0,2:0,25.100%=80%
b)$n_{H_2} pu=n_{CuO} pu=0,2(mol)$
$V_{H_2}=0,2.22,4=4,48(lit)$
 
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