[hóa 12] PVC

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suachua95

Trả lời

[TEX]2CH_4\rightarrow \ (-CH_2-CHCl_)[/TEX]
[TEX]2n mol\rightarrow \62,5n [/TEX]
[TEX]x=?\rightarrow \ 10^6g [/TEX]
[TEX]X=V=10^6\frac{2n}{62,5n}\frac{100}{20}22,4=3584000lIT[/TEX]
 
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