[Hoá 12] kim loại kiềm

V

vy000

$n_{CO_2}=a --> n_{NaCl}=2a -->m_{\text{dd sau pu}}=585a$

--> $585a+44a=200+120$

--> tính
ĐA: 27%
 
H

hokthoi

[TEX]nCO_2 = a \Rightarrow nNaCl = 2a \Rightarrow m [/TEX]dd sau pư [TEX]= 120 + 200 - 44a[/TEX]

[TEX]\Rightarrow \frac{2a . 58,5}{320 - 44a} =0,2[/TEX]
 
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