[Hoá 12] bài này khó quá

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0samabinladen

[tex]Fe + 4HNO3---->Fe(NO_3)_3+NO+2H_2O[/tex]
0,1______0,4_________0,1

[tex]Fe + 2Fe^{3+}---->3Fe^{2+}[/tex]
0,02___0,04__________0,06

Khi cho phản ứng với Cu:
[tex]Fe^{3+} + 1e----->Fe^{2+}[/tex]
0,06_____0,06____0,06

[tex]Fe^{2+} + 2e----->Fe[/tex]
0,12___0,24____0,12

[tex]Cu - 2e---->Cu^{2+}[/tex]
0,15__0,3

-->[tex]m_{Cu}=64.0,3=19,2g[/tex]
 
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