hóa 11]

T

thupham22011998

$Zn+CdSO_4-->ZnSO_4+Cd$
0,04......0,04...........0,04.........0,04 mol

$m$ kim loại tăng = $m Cd-m Zn=1,88g$

-->$m Zn$ ban đầu$=80g$
 
You must log in or register to reply here.
Top Bottom