hóa 11

D

darkmoon97

S

shibatakeru

Gọi $n_{Fe}=x , n_{O_2 pu}=y$

$n_{\text{e nhường}}=3n_{Fe}+3n_{Al}=3x+3.0,1$

$n_{\text{e nhận}}=4n{O_2}+3n_{NO}=0,1.3+4y$

$3x+0,3=4y+0,3$

$56x+32y+2,7=18,7$

$x=0,2 ; y=0,15$
 
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