[Hoá 11] Muối NO3

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hoabattu162

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the_god

10gam Al(NO3)3 thu duoc 3,52 g chat ran X.

======Al(NO3)3===============>1/2Al2O3
ban dau 10/(27+62*3)mol
pứ______xmol__________________________1/2xmol
sau p ứng(10/(27+62*3)-x)________________1/2xmol

kluong sau pứ (10/(27+62*3)-x)*(27+62*3)+ 1/2X*102=3,52g

===> x=0.04 mol
cho vao nuoc thi có Al203 ko tan===> nAl203=0.02mol

mAl203=a=0,02*102=2.04g
 
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