[hóa 11]cân = hoá học

A

anhthu_1995

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H

hoan1793

$2Fe^{+2}=>2Fe{+3}+2e...x5$
Mn^{+7}+5e=>Mn^{+2}....x2
=>$10Fe^{+2}+2Mn^{+7}=>10Fe^{+3}+2Mn^{+2}$
=>10FeSO4+2KMnO4+16KHSO4
=>5Fe2(SO4)3+9K2SO4+2MnSO4+8H2O :D

FeSO4+K2Cr2O7+KHSO4=>Cr2(SO4)3+Fe2(SO4)3…
$2Fe^{+2}=>2Fe^{+3}+2e..x3$
$2Cr^{+6}+6e=>2Cr^{+3}..x1$
=>$6Fe^{+2}+2Cr^{+6}=>6Fe^{+3}+2Cr^{+3}$
=>6FeSO4+K2Cr2O4+14KHSO4
=>Cr2(SO4)3+3Fe2(SO4)3+8K2SO4+7H2O :D
 
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