[Hóa 11] Bài tập điện li

T

thupham22011998

$ CH_3COONa$ -->$ CH_3COO^-$$+Na^+ $
0,1M...........................0,1M
$CH_3COO^-+H_2O <-->CH_3COOH+OH^-$
Bđ: 0,1M
Pư: a.....................................a.................a
Sau: 0,1-a.............................a.................a

Kb=5,71.10^-10

--> $\frac{a^2}{0,1-a}=8,71.10^{-10}$

-->$a=7,56.10^{-6}$

-->$[H^+]=1,32.10^{-9}$ (Đáp án B)
 
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