[Hoá 11] Ancol kho'

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shaynethomaswardlonely

M

mystory

BTKL Thôi
[TEX]M_O_2 = 5,6 - 4 = 1,6 \Rightarrow n_O_2 = 0,05 mol[/TEX]

[TEX]RCH_2OH + 1/2 O_2 -> RCHO + H_2O[/TEX]
[TEX]\Rightarrow n_{RCH_2OH} = 0,1 mol[/TEX]
[TEX]M < 4/0,1 = 40[/TEX]
R<9 \Rightarrow R = 1 là H là Metanol
H = 80%
 
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