[Hoá 10]

C

chypkul99

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T

toiyeu9a3

$m_{Cl_2} = m_{NaCl} - m_{Na}$
$2NaCl ---> 2Na + Cl_2$
$n_{Cl_2} = \dfrac{1}{2}n_{Na} = \dfrac{1}{2}.\dfrac{29,89}{22,99}$
Nguyên tử khối của clo là: $\dfrac{1}{2}.\dfrac{m_{Cl_2}}{n_{Cl_2}}$
 
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