[Hoá 10] xác định nguyên tố

D

duykhoi97

S

shibatakeru

$n_{H_2}=0,672:22,4=0,03 (mol)$

$n_{A}=n_{H_2}=0,03 (mol)$

$M_A=1,52:0,03=50,67 (g/mol)$

$Fe=56 \rightarrow X<50,67$

$0,95 g X+0,05 mol HCl$ ,axit dư nên $X>38$

X là Ca
 
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