Hóa 10 PỨ OXH-K

T

thupham22011998

$MnO_2+4HCl -> MnCl_2 + Cl_2 + 2H_2O$

Ta có: n $Cl_2$=0,1 mol

Theo pthh,ta có: n $HCl=0,4 mol$

-->m d/d $HCl=73g$

-->V d/d $HCl=61ml$
 
You must log in or register to reply here.
Top Bottom