[hóa 10] phản ứng oxi hóa khử

H

hthtb22

1) $KI + HNO_3 -> I_2 + KNO_3 +NO +H_2O$
Mình làm mẫu nhá

$2I^{-1} \rightarrow I_2+2e|*3$
$N^{+5}+3e \rightarrow N^{+2}|*2$

$6KI + 8HNO_3 -> 3 I_2 + 6KNO_3 +2NO +4H_2O$
b.
$Cu+KNO_3+H_2SO_4 =>CuSO_4+K_2SO_4+NO+H_2O$

$Cu^{0}=>Cu^{+2}+2e|x3$
$N^{+5}+3e=>N^{+2}|x2$

$3Cu+2KNO_3+4H_2SO_4 =>3CuSO_4+2NO+K_2SO_4+4H_2O$
c.
$2KMnO_4 + 16HCl --> 2KCl + 2MnCl_2 + 8H_2O + 5Cl_2$

 
T

thongoc_97977

1) 3KI +4HNO3 ->3 /2 I2 + 3KNO3 +NO +2H2O
2)3Cu +2KNO3 + 4H2SO4 -> 3CuSO4 +K2SO4 +4NO +4H2O
3) 2KMnO4 + 16HCl -> 2MnCl2 + 2KCl +5 Cl2 + 8H2O
 
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