Hoá 10 oxit axit

N

namnguyen_94

Gọi n[TEX]BaSO_3[/TEX] = a mol ; n[TEX]Ba(HSO_3)_2[/TEX] = b mol
+ nBa(OH)2 = 0,075 mol --> a + b = 0,075
Ta có: m(giảm) = 217a - ( a + 2b).64 = 0,235
--> a = 0,035 mol ; b = 0,04 mol
--> nSO2 = 0,115 mol
--> V = 2,576 lít
 
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