[hóa 10] độ pH ?

V

vy000

$n_{H(Y)}=n_{H(X)}-2n_{H_2}=1.0,25+0,5.2.0,25-5,32:22,4.2=0,025 (mol)$

$[H^+(Y)]=0,025:0,25=0,1$

$pH(Y)=-\log[H^+(Y)]=1$
 
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