[Hóa 10] chuỗi phản ứng

B

be_mum_mim

Do không yêu cầu chuỗi thẳng hay nhánh nên mình vẽ chuỗi nhánh:
$NaCl<=> NaOH--->Na_2SO_3<=>SO_2---->SO_3---->H_2SO_4--->HNO_3---->Cl$
_________|
_________NaO______________
 
V

vy000

$NaCl \xrightarrow{dpnc} Na+Cl_2$
$NaCl+H_2O \xrightarrow{\text{điện phân dung dịch có màng ngăn}} NaOH+H_2+Cl_2$
$HCl+KMnO_4 \rightarrow KCl+MnCl_2+Cl_2+H_2O$
$HCl+MnO_2 \xrightarrow{t^o} MnCl_2+Cl_2+H_2O$
$HCl+K_2Cr_2O_7 \rightarrow KCl+CrCl_3+Cl_2+H_2O$
$HCl+KClO_3 \rightarrow KCl+Cl_2+H_2O$
$HCl+Na_2O_2 \rightarrow NaCl+Cl_2+H_2O$
$HCl \xrightarrow{dpdd} H_2+Cl_2$
$O_2+HCl \xrightarrow{400^oC}Cl_2+H_2O$
$O_3+HCl\rightarrow Cl_2+H_2O+O_2$
$NaClO+HCl \rightarrow NaCl+Cl_2+H_2O$
$CaOCl_2+HCl \rightarrow CaCl_2+Cl_2+H_2O$
 
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