hic, bài này ko khó nhưng ko biết làm

K

kachia_17

[tex]\huge y=\frac {2x-1}{x-2} =\frac{2x-4+3}{x-2}=\frac{2(x-2)+3}{x-2}=2+\frac{3}{x-2} \\ \ \\ y\in Z \rightarrow \frac 3{x-2}\in Z \rightarrow x-2= {-3;-1;1;3}[/tex]
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