[tex]tanAcos^2B=tanB.cos^2A<=>tanA.\frac{1}{tan^2B+1}=tanB.\frac{1}{tan^2A+1}<=>(tan^2A+1)tanA=tanB(tan^2B+1)<=>(tanA-tanB)(tan^2A+tanAtanB+tan^2B)+(tanA-tanB)=0<=>(tanA-tanB)(tan^2A+tanAtanB+tan^2B+1)=0[/tex]
Ma [tex]tan^2A+tanAtanB+tan^2B+1[/tex] luôn >0 => pt<=> tan A=tanB=> A=B => tam giác cân tại C