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trung70811av


bài 1:giải hpt sau
[TEX]\left{\begin{x^3+2y^2=x^2y+2xy}\\{x-2=2\sqrt{x^2-2y-1}+\sqrt[3]{y^3-14}}[/TEX]
[TEX]\left{\begin{x^3+2y^2=x^2y+2xy}\\{x-2=2\sqrt{x^2-2y-1}+\sqrt[3]{y^3-14}}[/TEX]