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[tex]PTHDGD:2ax^2-4x+2a^2=0[/tex]
PT có 2 nghiệm phân biệt $\Delta '=4-4a^3\geq 0\Leftrightarrow a\leq 1\Rightarrow 0<a\leq 1$
Xài Viete rồi thay vô thôi
$K=\frac{8}{x_M+x_N}+\frac{1}{2x_M.x_N}=\frac{8}{\frac{4}{2a}}+\frac{1}{2.\frac{2a^2}{2a}}=4a+\frac{1}{2a}\geq 2\sqrt{2}\\"="\Leftrightarrow a=\frac{1}{2\sqrt{2}}(TM: 0<a \leq 1)$