Giúp mình

7

74642123

H

heartrock_159

CnH2n+1OH + CuO = CnH2nO + Cu + H2O
mcr giảm = mO(CuO)=0,32g. nO=nCuO(ư)=0,32:16=0,02(mol)
nên nancol=nH2O=nCuO=0,02(mol)
Mhh(su)=(0,02.(14n+16)+0,02.18)/(0,02+0,02)=15,5.2=31
n=2
ancol: C2H5OH
m= 0,02.46=0,92
 
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