giup minh ti

T

tienkk777

N

ngocbangngoc

n Fe= n H2=0,1 mol
Sau phản ứng có : Cu, [TEX]Fe^{2+}, H^+ [/TEX]

3Cu +[TEX] 8H^+[/TEX] + [TEX]2NO3^-[/TEX]---------->[TEX]3Cu^{2+}[/TEX] + 2NO + 4H2O
0,1_________[TEX]\frac{1}{15}[/TEX]______________[TEX]_\frac{1}{15}[/TEX]

[TEX]3Fe^{2+}[/TEX] + 4[TEX]H^+[/TEX] +[TEX] NO3^-[/TEX] ----------->3[TEX]Fe^{3+}[/TEX] + NO + 2H2O
0,1_____________[TEX]\frac{1}{30}[/TEX]___________________0,1

[TEX]\Rightarrow[/TEX] n NO= 0,1 mol [TEX]\Rightarrow[/TEX] V = 2.24 l
 
K

kakashi_hatake

$4H^++NO_3^-+3e \rightarrow NO+2H_2O \\ n_{KNO_3}=0,1=n_{NO} \rightarrow V=2,24l \ (H^+ \ dư)$
 
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