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wian96


a)tan^2 y (1-sin^3 y)+cos^3 y - 1 =0
b)cos^6 x - sin^6 x = \frac{13}{8}cos^2 2x
c)sinx-4sin^3 x + cosx = 0
d)tan 2x + sin 2x =\frac{3}{2}cot x
b)cos^6 x - sin^6 x = \frac{13}{8}cos^2 2x
c)sinx-4sin^3 x + cosx = 0
d)tan 2x + sin 2x =\frac{3}{2}cot x