Giúp mình câu về glixerol

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trollhk

C3H5(OH)3+3CH3COOH->(CH3COO)3C3H5+3H2O
nC3H5(OH)3=0,1
nCH3COOH=0,15=>nC3H5(OH)3 du
nCH3COOH=0,15=>n(CH3COO)3C3H5=0,05=>m(…
H=60%=>m(CH3COO)3C3H5 thuc te thu duoc la 10,9x60/100=6,54g
 
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