[tex]y=0[/tex] ko phải nghiệm, chia 2 vế cho y:
[tex]2\left ( y+\frac{1}{y} \right )-3\left ( \sqrt{y}+ \frac{1}{\sqrt{y}}\right )-1=0[/tex]
Đặt [tex]\sqrt{y}+\frac{1}{\sqrt{y}}=t\geq 2\Rightarrow y+\frac{1}{y}=t^2-2[/tex]
[tex]\Rightarrow 2(t^2-2)-3t-1=0[/tex]