![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
Giải cá phương trình sau:
a, [tex]\left ( x^{2}-1 \right )(x+2)(x-3)=(x-1)(x^{2}-4)(x+5)[/tex]
b, [tex]x^{4} - 4x^{3} + 3x^{2} + 4x -4[/tex] = 0
a, [tex]\left ( x^{2}-1 \right )(x+2)(x-3)=(x-1)(x^{2}-4)(x+5)[/tex]
b, [tex]x^{4} - 4x^{3} + 3x^{2} + 4x -4[/tex] = 0