1/(x+2)(x+3)+1/(x+3)(x+4)+1/(x+4)(x+5)+1/(x+5)(x+6)=1/15
->1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)+1/(x+4)-1/(x+5)+1/(x+5)-1/(x+6)=1/15
->1/(x+2)-1/(x+6)=1/15
-> 4/(x+2)(x+6)=1/15
->4/(x+2)(x+6)=4/60
-> (x+2)(x+6)=60
-> x^2+8x+12=60
-> x^2+8x+16=64
->(x+4)^2=64
-> x+4=8 hoặc x+4=-8
-> x=4 hoặc x=-12