giải phương trình sau

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dien0709

$6\sqrt[]{x^2+x+1}=6+5x+4x^2 -2x^3 –x^4$

$<=>\dfrac{6(x^2+x)}{\sqrt{x^2+x+1}+1}=5x+4x^2-2x^3-x^4<=>x=0$

$6(x+1)=(\sqrt{x^2+x+1}+1)(x+1)(-x^2-x+5)<=>x=-1$

$6=(\sqrt{x^2+x+1}+1)(-x^2-x+5)$ , $t=\sqrt{x^2+x+1}>0$

$<=>6=(t+1)(6-t^2)<=>...$
 
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