[tex]cos2x+\sqrt{3}sin2x+\sqrt{3}sinx-cosx=2\\\Leftrightarrow \frac{1}{2}cos2x+\frac{\sqrt{3}}{2}sin2x+\frac{\sqrt{3}}{2}sinx-\frac{1}{2}cosx=1\\\Leftrightarrow cos(2x-\frac{\pi}{3})+sin(x-\frac{\pi}{6})=1\\x-\frac{\pi}{6}=t\\PT\Leftrightarrow cos2t+sint=1\\\Leftrightarrow 1-2sin^2t+sint=1\\\Leftrightarrow 2sin^2t-sint=0\\\Leftrightarrow sint(2sint-1)=0\\\Leftrightarrow \left[\begin{array}{l} sin(x-\frac{\pi}{6})=0\\sin(x-\frac{\pi}{6})=\frac{1}{2} \end{array}\right.[/tex]
Làm nốt nhé :v