sin(3x+pi/5)+sin(4pi/5-3x)=√3
Lần sau bạn gõ latex ra để dễ nhìn hơn nhé
[tex]sin(3x+\frac{\Pi}{5}) + sin( \frac{4\Pi}{5}-3x)=\sqrt{3}[/tex]
[tex]\Leftrightarrow 2.sin\frac{\pi}{2}.cos(3x-\frac{3\pi}{10})=\sqrt{3}[/tex]
[tex]<=>cos(3x-\frac{3\pi}{10})=\frac{\sqrt{3}}{2}[/tex]
[tex]\Leftrightarrow cos(3x-\frac{3\pi}{10})= cos\frac{\pi}{6}[/tex]
[tex]\Leftrightarrow \left\{\begin{matrix} 3x & -\frac{3\pi}{10} & =\frac{\pi}{6}+k2\pi\\ 3x & -\frac{3\pi}{10} & = -\frac{\pi}{6}+k2\pi \end{matrix}\right.[/tex]
[tex]\Leftrightarrow \left\{\begin{matrix} x & = & \frac{7\pi}{45}+\frac{k2\pi}{3}\\ x & = & \frac{-7\pi}{45}+\frac{k2\pi}{3} \end{matrix}\right.[/tex] ([tex]k\in \mathbb{Z}[/tex])
=> Kết luận