giải hpt

L

lp_qt

$\left\{\begin{matrix}x^{2}+y^{2}+xy=1 & \\ x^{3}+y^{3}=x+3y & \end{matrix}\right.$

\Rightarrow $x^{3}+xy^{2}+3x^{2}y+3y^{3}+x^{2}y+3xy^{2}=x^{3}+y^{3}$

\Leftrightarrow $2y^{3}+4x^{2}y+4xy^{2}=0$

\Leftrightarrow $y(y^{2}+2xy+2x^{2})=0$

\Leftrightarrow $y=0$

\Rightarrow $x=\pm 1$
 
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