Giải các ptr lượng giác

C

connguoivietnam

1)
[TEX]2sin^22x+ sin7x-1=sinx[/TEX]
[TEX]1-cos4x+sin7x-1-sinx=0[/TEX]
[TEX]2cos4xsin3x-cos4x=0[/TEX]
[TEX]cos4x(2sin3x-1)=0[/TEX]
2)
[TEX]5(sinx+\frac{cos3x+sin3x}{1+2sin2x})=cos2x+ 3[/TEX]
[TEX]sin2x[/TEX] khác [TEX]\frac{-1}{2}[/TEX]
[TEX]5[sinx(1+2sin2x)+cos3x+sin3x]=(cos2x+3)(1+2sin2x)[/TEX]
[TEX]5[sinx+2sin2xsinx+cos3x+sin3x]=(cos2x+3)(1+2sin2x)[/TEX]
[TEX]5[sinx+cosx+sin3x]=(cos2x+3)(1+2sin2x)[/TEX]
[TEX]5[2sin2xcosx+cosx]=(cos2x+3)(1+2sin2x)[/TEX]
[TEX]5cosx[2sin2x+1]=(cos2x+3)(1+2sin2x)[/TEX]
[TEX](2sin2x+1)(5cosx-cos2x-3)=0[/TEX]
 
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