tìm x : /x-3/+/3x+4/=/2x+1/
$|x-3|+|3x+4|\geq |x-3+3x+4|=|4x+1|\geq |2x+1|$
Dấu '=' xảy ra khi $\left\{\begin{matrix} (x-3)(3x+4)\ge 0 \\ |4x+1|=|2x+1| \end{matrix} \right.\Leftrightarrow \left\{\begin{matrix} x\ge 3 \ or \ x\le \dfrac{-4}3 \\ x=0 \ or \ x=\dfrac{-1}3 \end{matrix} \right.\Leftrightarrow x=\emptyset$