gai he phuong trinh sau

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nguyenbahiep1

[laTEX]e^x.tanx = e^y.tany \\ \\ f(t) = e^t.tant \\ \\ f'(t) = e^t.tant + e^t.(1+tan^2t) = e^t(1+tant+tan^2t) \\ \\ f'(t) = e^t.[ ( tant + \frac{1}{2})^2 + \frac{3}{4}] > 0 \\ \\ f(t) - dong-bien \\ \\ f(x) = f(y) \Rightarrow x= y \\ \\ 2x^3 - x^2-2x+1 = 0 \Rightarrow x=y = \pm1 , \frac{1}{2}[/laTEX]
 
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