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nguyenbahiep1

[laTEX]\sqrt{5x^3+3x^2+3x-2} +\frac{1}{2}=\frac{x^2}{2}+3x \\ \\ 2\sqrt{5x^3+3x^2+3x-2} = x^2 +6x-1 \\ \\ 2\sqrt{5x^3+3x^2+3x-2} = x^2 -4x +3 +10x -4 \\ \\ 2\sqrt{5x^3+3x^2+3x-2} - (10x-4) = (x-1)(x-3) \\ \\ \frac{4(x-3)(x-1)(5x-2)}{2\sqrt{5x^3+3x^2+3x-2} + (10x-4)} = (x-1)(x-3) \\ \\ x = 1 , x = 3 [/laTEX]
 
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