đại số 7

P

pinkylun

ta có:
$2^2 +4^2 +6^2 +...+20^2 $
=$2^2+2^2.2^2+2^2.3^2+...+2^2.10^2$
=$2^2(1+2^2+3^2+...+10^2)$
=$4.385$
=$1540$
 
T

thieukhang61

\[\begin{array}{l}
Ta\,\,co:\,\\
{2^2} + {4^2} + {6^2} + ... + {20^2}\\
= {2^2}.({1^2} + {2^2} + {3^2} + ... + {10^2})\\
= 4.385\\
= 1540
\end{array}\]
 
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