đại sô 7

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khaiproqn81

$x+6=\dfrac{-7}{3} \to x=\dfrac{-25}{3} \\ x+z=\dfrac{1}{2} \to\dfrac{-25}{3}+z=\dfrac{1}{2} \to z=\dfrac{53}{6} \\ y+z=\dfrac{1}{4} \to \dfrac{53}{6}+y=\dfrac{1}{4} \to y= \dfrac{-103}{12}$
 
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