[Đại 7] Rút gọn

M

minhhieupy2000


$\dfrac{a^4+b^4+(a+b)^4}{a^2+b^2+(a+b)^2} = \dfrac{a^4+b^4+(7+ab)^2}{2(a^2+b^2+ab)} = \dfrac{a^4+b^4+a^2b^2+14ab+49}{14} = \dfrac{a^4+b^4+a^2b^2+2ab(a^2+b^2+ab)+49}{14} = \dfrac{(a^2+b^2+ab)^2+49}{14} = 4$
 
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