cong thuc luong giac

T

tunglam_95_01

Bai 2: cm :cotx-tanx=2cot2x.
Dk:sin2x khac 0
<=>cosx/sinx-sinx/cosx=2cos2x/2sinxcosx
<=>(cos^2 x-sin^2 x)/sinxcosx=cos2x/sinx cosx
<=>cos^2 x-sin^2 x=cos^2x (dpcm)
Cau 3: sinx+sin2x+...+sinnx=1/2cot(x/2)cos[(n+1/2)x]/2sin(x/2) chi biet ket qua vay....
 
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