b.Đặt [tex]\frac{a}{2016}=\frac{b}{2017}=\frac{c}{2018}=k[/tex]
=>a=2016k
=>b=2017k
=>c=2018k
Do đó :M=4(a-b)(b-c)-[tex](c-a)^{2}[/tex]
=4(2016k-2017k)(2017k-2018k)-[tex](2018k-2016k)^{2}[/tex]
=4.(-k).(-k)-[tex](2k)^{2}[/tex]
=[tex]4k^{2}[/tex]-[tex]4k^{2}[/tex]
=0
Vậy M=0
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