[tex](a+b+c)^{3}=a^{3}+b^{3}+c^{3}+3(a+b)(b+c)(c+a)[/tex]
Ta có:
[tex](a+b+c)^3=(a+b)^3+c^3+3(a+b)c(a+b+c)=a^3+b^3+3ab(a+b)+c^3+3(a+b)c(a+b+c)\\ =a^3+b^3+c^3+3(a+b)(ab+c(a+b+c))\\ =a^3+b^3+c^3+3(a+b)(ab+ca+cb+c^2)=a^3+b^3+c^3+3(a+b)(a+c)(b+c)\\ =>dpcm[/tex]