BT về axit !

H

huyhoang94

M

mobile_lam

Ta có
[TEX]n _{hh}=0.2 \ mol \Rightarrow M _{TB}=77.6 \ n _{CO _{2} }=0.48 \Rightarrow C _{TB}=2.4 [/TEX]
Vậy 2 axit là:
[TEX]{\color{blue} CH _{3} -COOH} [/TEX]
[TEX]{\color{blue} HOOC-CH _{2} -COOH} [/TEX]
 
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