BT sinh 9

N

ngocsangnam12

0,51 micromet = $10^4$ . 0,51= 5100 $A^o$
tổng số nu kủa gen N=$\frac{2*l}{3,4}$=$\frac{2*5100}{3,4}$= 3000(nu)
Ta có A = T = 900
G=X=$\frac{3000 - 900*2}{2}$ = 600
 
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