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[TEX]\left{\begin{Na: 2x mol}\\{Ba:2y mol}\\{K:2z mol} [/TEX]
BTNT H=> [TEX]2x+4y+2z=0.5(1)[/TEX]
[TEX]1/2 ddA=> \left{\begin{NaOH:xmol}\\{Ba(OH)_2:y mol}\\{KOH:z mol [/TEX]
[TEX]=> \left{\begin{Na_2S04:x/2 mol}\\{BaS04:ymol}\\{K_2S04:z/2 mol} [/TEX]
[TEX]=> nS042-=\frac{x}{2}+y+\frac{z}{2}[/TEX]
m Muối[TEX]= 23,8+\frac{x}{2}+y+\frac{z}{2}[/TEX]
Từ(1)=> m Muối=36.05g
 
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