Bđt

V

vodichhocmai

$$ \huge \dfrac{1}{{a}^{2}}+\dfrac{1}{{b}^{2}}+\dfrac{1}{{c}^{2}} \ge \dfrac{a+b+c}{abc} \ge \dfrac{27}{(ab+bc+ca)^2}=\dfrac{27(a^2+b^2+c^2)}{(ab+bc+ca)^2(a^2+b^2+c^2)}\ge a^2+b^2+c^2$$
 
C

conga222222

her her ..............................................................................................................................................................................................................
 
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