[BĐT 8] Cm: $\frac{1}{2}<\frac{1}{n+1}+\frac{1}{n+2}+\frac{1}{ n+3}+....+\frac{1}{n+n}<\frac{3}{4}$

X

xuanquynh97

$\dfrac{1}{n+1} > \dfrac{1}{n+n}$

$\dfrac{1}{n+2} > \dfrac{1}{n+n}$

...

$\dfrac{1}{n+n-1} > \dfrac{1}{n+n}$

\Rightarrow P > $\dfrac{n}{n+n}=\dfrac{1}{2}$
 
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